The height of a volleyball, h, in feet, is given by h = −16t^2 + 11t + 5.5, where t is the number of seconds after it has been hit by a player. The top of the net is 7.3 feet above the floor. Does the volleyball travel high enough to clear the top of the net? Please help me answer the steps attached below.

The volleyball travel high enough to clear the top of the net.

Step-by-step explanation:

The height of a volleyball, h, in feet, is given by h = −16t² + 11t + 5.5, where t is the number of seconds after it has been hit by a player.

Now, for h = 7.3 feet, we can write

7.3 = - 16t² + 11t + 5.5

⇒ 16t² - 11y + 1.8 = 0

Using the quadratic formula we get,

⇒

⇒ t = 0.27 or t = 0.42

Therefore, for the two real positive values of t the volleyball travel high enough to clear the top of the net. (Answer)

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt