What is the probability of rolling a three on the first die and an even number on the second die?

Rolling a 3: 1 out of 6

Rolling an even number: 3 out of 12

Just remember the sides of your dice.

1 2 3 4 5 6

The question is asking the probability of getting a 3. Well there is ONE 3 out of 6 numbers so 1 out of 6.

1 2 3 4 5 6

Now the second part is asking for an even number. There are THREE even numbers on a dice so it'll be 3 out of 6 but now this is the SECOND ROLL so it'll be 3 out of 12

1 2 3 4 5 6

I put the numbers to explain it a little better in bold, underlined and italicized.

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb