please answer Which value of x is a solution to this equation?
5x^2-36x+36=0

x = -6

x=-1.8

x=4

x=1.2

1.2

Step-by-step explanation:

1) factor this equation:

36*5=180

so what*what=180

and what+what=-36

-30*-6=180

and

-30-6=-36

substitute -30x and -6x in place of -36x

5x^2-30x-6x+36

split in two groups:

group a) 5x^2-30x

(gcf of 5x)

5x(x-6)

group b) -6x+36

-6(x-6)

(5x-6)(x-6)=0

5x-6=6/5 or 1.2

x-6=6

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.