Find the distance between the points (-2,3) and (3,-9)

  13 units

Step-by-step explanation:

Put the numbers in the distance formula and do the arithmetic.

  d = √((x2 -x1)² +(y2 -y1)²)

  = √((3 -(-2))² +(-9-3)²) = √(5² +(-12)²) = √(25 +144)

  d = √169 = 13

The distance between the points is 13 units.

omg what happend to your question? if you could edit this question i can

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.