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Mathematics, 08.04.2020 18:57 strodersage

Given two functions j(x)=βˆ’6x+2 and k(x)=2+4x , what is the function rule for (kj)(x) ? (kj)(x)=βˆ’24x2+4x+4 (kj)(x)=24x2βˆ’4x+4 (kj)(x)=24x2βˆ’4xβˆ’4 (kj)(x)=βˆ’24x2βˆ’4x+4

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Given two functions j(x)=βˆ’6x+2 and k(x)=2+4x , what is the function rule for (kj)(x) ? (kj)(x)=βˆ’24x2...
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