A local business has 1492 employees. The number of employees who have children is 966. The number of employees who drive to work is 488. If the probability that an
employee has children or drives to work is 621/746, what is the probability that an employee has children and drives to work?

A∩B= 212/1492 = 53/373

Step-by-step explanation:

Let the number of employees who have children is A and the number of employees who drive to work is B. Then we have these values

A= 966/ 1492

B= 488/ 1492

A or B = A ∪ B = 621/746 = 1242/1492

The question is asking the probability that an employee has children and drives to work(A∩B). Using the union formula, we can find the answer. The calculation will be:

A ∪ B = A + B - A∩B

1242/1492 = 966/ 1492 +  488/ 1492 - A∩B

A∩B= 1454/1492- 1242/1492

A∩B= 212/1492= 53/373

the answer is 5/3x+7/5y+7

16.9 times 2.85

step-by-step explanation: