You might need: Calculator Problem Suppose that Antonia rolls a pair of fair six-sided dice. Let AAA be the event that the first die lands on 555 and BBB be the event that the sum of the two dice is 666. Using the sample space of possible outcomes below, answer each of the following questions. What is P(A)P(A)P, (, A, ), the probability that the first die lands on 555

P(A)=1/6

Step-by-step explanation:

The sample space of the two dice is given below:

[1, 1], [1, 2], [1, 3], [1, 4], [1, 5], [1, 6]

[2, 1], [2, 2], [2, 3], [2, 4], [2, 5], [2, 6]

[3, 1], [3, 2], [3, 3], [3, 4], [3, 5], [3, 6]

[4, 1], [4, 2], [4, 3], [4, 4], [4, 5], [4, 6]

[5, 1], [5, 2], [5, 3], [5, 4], [5, 5], [5, 6]

[6, 1], [6, 2], [6, 3], [6, 4], [6, 5], [6, 6]

n(S)=36

Let A be the event that the first die lands on 5

Sample Space of Event A is:

[5, 1], [5, 2], [5, 3], [5, 4], [5, 5], [5, 6]

n(A)=6

Therefore:

P(A)=n(A)/n(S)

=6/36

=1/6

answer: for each 3 girls there is 2 boys . 3: 2

hope this ! (:   mark me as brainliest if you can

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step-by-step explanation: