If a baseball player's batting average is 0.340 (i. e., the probability of getting a hit each time at bat is 0.340), find the probability that the player will have a bad season and get at most 60 hits in 200 times at bat

13.1%

Step-by-step explanation:

Given:

N = 200  

P= 0.34

0<= x <=60

x= number of hits.

n=total times at bat

In order to find mean, we take the product of n and p, therefore:

mean 'μ' = np = 200 x  0.34 = 68

next is to find standard deviation, i.e the square root of the product of n, p and q

where q is 1-p

SD 'σ' = sqrt(npq) = sqrt(68*0.66) = 6.6993  

applying continuity correction,

z = (x - μ) / σ    

z = (60 - 68) /6.6993 = - 1.12

For the normal standard distribution,

P(z < - 1.12) = 13.14% => 13.1%

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180