Part A: Consider the equation x + 7 = 16. Which number from the set {5, 7, 9, 11} makes the equation true?

Part B: If the equation above was changed to the inequality x + 7 < 16, would the same number make the inequality true? Explain why or why not.

Do any numbers from the set given in Part A satisfy the inequality? If so, which ones?

Part A: Substitute/plug in each number into the equation to see which number will make the equation true.

x + 7 = 16      Plug in 5 into "x"

5 + 7 = 16

12 = 16    5 doesn't make the equation true because it equals 12 not 16

x + 7 = 16     Plug in 7 into "x"

7 + 7 = 16

14 = 16     7 doesn't make the equation true because it equals 14 not 16

x + 7 = 16     Plug in 9 into "x"

9 + 7 = 16

16 = 16             9 makes the equation true because it equals 16

Part B: Plug in 9 into "x" in the inequality to see if it still makes it true.

x + 7 < 16     [x plus 7 is less than 16]

9 + 7 < 16

16 < 16     [16 is less than 16]  The same number would not make the inequality true because 16 can't be less than itself.

To figure out which numbers satisfy the inequality, plug it into the inequality:

x + 7 < 16      Plug in 5 into "x"

5 + 7 < 16

12 < 16      5 does satisfy the inequality because 12 is less than 16

x + 7 < 16     Plug in 7 into "x"

14 < 16     7 does satisfy the inequality because 14 is less than 16

x + 7 < 16     Plug in 11 into "x"

11 + 7 < 16

18 < 16     11 doesn't satisfy the inequality because 18 isn't less than 16

1/4 and 8/3 because:

the reciprocal if 4 is 1/4 because 4 is used as 4/1 and the opposite of that is 1/4. the opposite of 3/8 is 8/3 so that is the answer.