Cara is playing a number game where she has two tiles for each number 0 to 9. A tile is chosen at random. How many favorable outcomes are there for choosing a multiple of 3?

Step-by-step explanation:

The number of possible numbers on the tile are:

0, 1 , 2 , 3 , 4,  5,  6,  7 ,  8 and 9.

Now, the chosen tile can have any of the ten options mentioned above.

The favorable outcomes are  3 , 6 and 9 as they are the multiple of 3.

So, the number of possible favorable outcomes  = 3 ways

Hence, if a card is chosen at random, there are 3 possible favorable outcomes for choosing a multiple of 3.

if im undersanding the question correctly, its organized from 10

step-by-step explanation:

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb