Suppose that the functions S and tea are defined for all real numbers X as follows S(x)=x-5 t(x)=3xsqaured write the expression for (t-s)(x) and (t+s)(x) and evaluate (t•s)(3)

The correct answer is (t-s)(x) = 3 - x + 5; (t+s)(x) = 3 + x - 5; (t·s)(3) = -54.

Step-by-step explanation:

Function s is defined as the following: s(x) = x - 5.

Function t is defined as the following:  t(x) = 3 .

Assuming that the two functions are defined on the same domain,

(t-s)(x) = t(x) - s(x) = 3 - x + 5.

(t+s)(x) = t(x) + s(x) = 3 + x - 5.

(t·s)(x) = t(x) × s(x) = 3 × (x -5)

(t·s)(3) = t(3) × s(3) = 3 × × (3 -5) = - 54

The required functions are given above and the value of the multiplication function at x = 3 is -54.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

step-by-step explanation: