Please Help!
The area of a rectangle is x^2 + 7x + 6. What is the perimeter of this rectangle?

 The perimeter would be  2(x+1) + 2(x+6) or  4x + 14

Such a rectangle does not really exist!

If you factor and solve for x, you get {-1,-6} Real Rectangles cannot have negative dimensions.

Step-by-step explanation: Factoring to find out which theoretical dimensions were multiplied to get the imaginary area you get (x + 1) and (x + 6).

Perimeter is  Twice the length plus Twice the width. So substitute the "dimensions" into the formula to get 2(x+1) + 2(x+6)  distribute and simplify

2x + 2 + 2x + 12 = 4x + 14

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

6/20

step-by-step explanation: