Among all monthly bills from a certain credit card company, the mean amount billed was $485 and the standard deviation was $300. In addition, for 15% of the bills, the amount billed was greater than $1000. A sample of 900 bills is drawn. What is the probability that the average amount billed on the sample bills is greater than $500? What is the probability that more than 150 of the sampled bills are for amounts greater than $1000

Step-by-step explanation:

a.

Let X be the amount paid by a certain credit card service.

From the details supplied, the X-bar is $485, the standard deviation is $300 and n=900.

By the central limit theorem when the sample size is high, the sample mean fits the normal distribution with the mean μ and the standard deviation function

So the likelihood that the total sum paid on the sample bills is greater than $500 is seen.

= P ( Z > 1.5 )

                         = 1 - 0.93319 { From excel function =NORM.DIST(1.5,0,1,TRUE)

                         = 0.0668

Thus, the probability that the average amount billed on the sample bills is greater than $500 is 0.0668.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3