Two cars leave an intersection at the same time. One heads due south at 55 mph. The other travels due west. After 2 hours, the bearing of the car headed west from the car headed south is 324 . How far apart are they at that time?

136 miles

Step-by-step explanation:

Distance is product of speed and time.

Given the car that moves South takes 2 hours then the speed is 55 mph

D=st

Where s is speed, t is time and D is distance covered. Substituting 2 hours for time and 55 mph for s then

Distance=2*55=110 miles

Using trigonometry

Cos 36°=110/x

X=110/cos 36°=135.967477524977 miles

Alternatively

X=110/sin 54°=135.967477524977

Rounded off, this is approximately 136 miles

answer: a and c are correct

step-by-step explanation:

the +5 is the vertical translation

the added negative symbol in front is the reflection over the y-axis

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2