The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Find the two weights that separate the top 3% and the bottom 3%. These weights could serve as limits used to identify which components should be rejected. Round to the nearest hundredth of a gram. 8.00 g and 8.02 g 7.88 g and 8.17 g 7.98 g and 8.04 g 7.90 g and 8.12 g

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.03

P(X > x)  

Calculation the value from standard normal z table, we have,  

Thus, 8.17 g separates the top 3% of the weights.

P(X < x)  

Calculation the value from standard normal z table, we have,  

Thus, 7.90 separates the bottom 3% of the weights.

Thus, the correct answer is

Option D) 7.90 g and 8.12 g

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24