Daily usage is exactly 60 gallons per day. Lead time is normally distributed with a mean of 10 days and a standard deviation of 2 days. What is the standard deviation of demand during lead time

The standard deviation of demand during lead time is 60*2

Step-by-step explanation:

Let us recall the following statements from the given question,

The daily usage is  =  60 gallons per day,

Then,

The total number of gallons that is used during the mean time lead  can be referred  to the demand mean amount:

The Mean demand amount = Daily usage x  Mean lead time

Mean demand amount = (60 gallons / day) x 10 days

Mean demand amount = 600 gallons

Since the standard deviation of the lead time is 2 days, the standard deviation of the demand should also be:

The Standard deviation of demand =  The Daily usage x Standard deviation of lead time

Standard deviation of demand = (60 gallons / day) x 2 days

Standard deviation of demand = 120 gallons

Or  60 times 2 or 60 x 2

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

answer: i think it's a

step-by-step explanation: