Whats the center and radius of (x+3)^2+(y-5)^2=64

The answer to your question is Center = (-3, 5)  radius = 8

Step-by-step explanation:

Data

                (x + 3)²  +  (y - 5)² = 64

Process

Because of the characteristics of the equation, we conclude that it is a circle.

Standard form of a circle:

              (x - h)² + (y - k)² = r²

In this form of the equation, the center has coordinates (h, k), just change the signs.

And to get the radius, just get the square root of r²

h = -3

k = 5

r = 8

Center = (-3, 5)

radius = 8

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

28

step-by-step explanation:

because that's the answer