In how many ways can $3$ identical red balls, $3$ identical green balls, and $3$ identical blue balls be arranged in a $3\times 3$ grid, such that each row and each column of the grid contains $1$ ball of each color

Step-by-step explanation:

GIVEN: identical red balls, identical green balls, and identical blue balls be arranged in a grid.

TO FIND: In how many ways can balls be arranged such that each row and each column contains ball of each color.

SOLUTION:

As each column and row must contain a red,a green and a blue ball.

Consider the image attached

each column contains a green,a blue and a red ball

To find more number of ways of arrangement, columns can be arranged differently such that each row will still contain each of three ball.

Now,

Total number of ways of arranging columns

Hence total number of ways such that each row and each column of the grid contains ball of each color is

answer: 12

step-by-step explanation:

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.