Geometry need with proofs

in δabc shown below, segment de is parallel to segment ac:

triangles abc and dbe where de is parallel to ac

the following two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally:

statement reason
1. line segment de is parallel to line segment ac 1. given
2. line segment ab is a transversal that intersects two parallel lines. 2. conclusion from statement 1.
3. ∠bde ≅ ∠bac 3. corresponding angles postulate
4.? 4.?
5.? 5.?
6. bd over ba equals be over bc 6. converse of the side-side-side similarity theorem

which statement and reason accurately completes the proof?

4. δbde ~ δbac; side-angle-side (sas) similarity postulate

5. ∠b ≅ ∠b; reflexive property of equality

4. ∠b ≅ ∠b; reflexive property of equality

5. δbde ~ δbac; angle-angle (aa) similarity postulate

4. δbde ~ δbac; side-angle-side (sas) similarity postulate

5. ∠a ≅ ∠c; isosceles triangle theorem

4. ∠a ≅ ∠c; isosceles triangle theorem

5. δbde ~ δbac; angle-angle (aa) similarity postulate