In a geometric progression, the sum of the 2nd term and the 3rd term is 36. The sum of the 3rd term and 4th term is 12. Find the 1st term and the common ratio.

a₀ = 81, r = 1/3

Step-by-step explanation:

a, b, c, d, ....

                     b + c = 36    →     b = 36 - c

                     c + d = 12     →     d = 12 - c

Use substitution method to solve for c:

Plug in c = 9 to find the common ratio (r):

Find the first term (a₀) using a₃ = 9:

can you give me more detail on this! ?

step-by-step explanation:

h df tyjgtyj ttd y ytkgfty ty

step-by-step explanation:

tyty jry j y yj yttj yhgtyj y ghyj ytthj