What is the probability that Bo, Colleen, Jeff, and Rohini win the first, second, third, and fourth prizes, respectively, in a drawing if 48 people enter a contest and winning more than one prize is allowed

1/4669920

Step-by-step explanation:

First if all, when repetition is mot allowed, we use Permutation to get the number of possible outcomes as follows;

P(n, r) = n!/(n - r)!

Now, the order is important since the first, second, third and fourth prizes are different.

Thus, we need to define the Permutation.

We need to select 4 winners of the 48 people.

Thus, n = 48 and r = 4

Thus;

P(48,4) = 48!/(48 - 4)!

P(48,4) = 4669920

Now, probability is the number of favourable outcomes divided by number of possible outcomes

Thus,

Probability = 1/4669920

answer: a

step-by-step explanation:

if xy ~ yz therefore xy would be the same length as yz

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: