Suppose that a bored student wants to go to a restaurant for lunch, but she only has an hour in which to go, eat, and get back in time for class. Considering that it usually takes about 30 minutes in most restaurants to get served and to eat, what is the farthest restaurant the student can go to without being late for class

Missing information

Take local speed ad 30 mph and express your answer in miles

7.5 miles

Step-by-step explanation:

Time for lunch is 1 hour but once will wait for 30 minutes before served and eat.

Out of 1 hour, 30 mins is for service and eating to mean time to get from work to restaurant, to and fro is the other 30 mins

Since 30 mins is for to and fro, then one way direction takes 15 mins.

Speed, s=d/t and distance d=speed*time

Given local speed of 30 mph and time as 15 mins,

To convert minutes to hours, we divide it by 60 hence the distance is

30*15/60=7.5 miles

Therefore, the student can go to a restaurant that is 7.5 miles from the office.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

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step-by-step explanation: