Find the value of a.2004-04-01-01-00_files/i015.jpg

are you familiar with the pythagorean theorem?
it's the formula a^2 + b^2 = c^2 where 'a' and 'b' are the legs of a right triangle, c is the hypotenuse
so here,
lets take
a = unknown, b = 18, c = 36If we focus on triangle ABC, we see that AC is the hypotenuse If we turn our attention to triangle ADB, we'll find that AB is the hypotenuse So they are corresponding partAD is the longer leg of triangle ADB AB is the longer leg of triangle ABC so this is another pair of corresponding partswe then divide the corresponding parts of ABC over ADB (in the same order) like this AC/AB = AB/AD then plug in the info we know 36/(18*sqrt(3)) = (18*sqrt(3))/AD and then solve for ADcross multiply to get 36*AD = (18*sqrt(3))(18*sqrt(3)) 36*AD = 18*18*sqrt(3)*sqrt(3)  36*AD = 18^2*(sqrt(3))^2 36*AD = 324*3 36*AD = 972 AD = 972/36AD = 27hope u get it :)

Dis a correct answer

Maybe fx = lxl because of the way the x is positioned is that what he