The diameters of ball bearings are distributed normally. The mean diameter is 135 millimeters and the variance is 4. Find the probability that the diameter of a selected bearing is greater than 132 millimeters. Round your answer to four decimal places.

0.9332

Step-by-step explanation:

The variance is 4, so the standard deviation is √4 = 2.

Calculate the z-score:

z = (x − μ) / σ

z = (132 − 135) / 2

z = -1.5

Use a table or calculator to find the probability.

P(Z > -1.5) = 1 − 0.0668

P(Z > -1.5) = 0.9332

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step-by-step explanation:

1,589.63 in.^3

step-by-step explanation:

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