If f(x)= cos(t^2)dt for -2.5≤x≤2.5, on which interval is f increasing?

[-2.5, 2.17) U (-1.25, 1.25) U (2.17, 2.5]

Step-by-step explanation:

Function is increasing when

f'(x) > 0

f'(x) = cos(x²)

cos(x²) > 0

When x² is:

0《x² < pi/2

3pi/2 < x²《2.5²

0《x² < 1.570796327

-1.253314137 < x < 1.253314137

4.71238898 < x²《6.25

-2.5《x < 2.170803764

2.170803764 < x《2.5

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere

the answer is mp

step-by-step explanation: