Mathematics, 07.04.2020 04:53 alizeleach0123
In triangle ABC, B = 50°, the length of side AB is 8 cm and the length of side BC is 5. Find the length of side AC using the law of cosines.
Answers: 3
= 
+ 
- 2ab(cosC)
+ 
- 2(5)(8)(cos50º)
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In triangle ABC, B = 50°, the length of side AB is 8 cm and the length of side BC is 5. Find the len...
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