What is the slope intercept form of the equation of the line that passes through the point (-6 ,1) and is perpendicular to the graph of 2x + 3y = -5

y = (3/2)x + 10

Step-by-step explanation:

2x + 3y = -5

3y = - 2x - 5

y = (-2/3)x - 5/3

The slope of the original line is -2/3, so the slope of the perpendicular line is 3/2. So now we have the perpendicular line as y = (3/2)x + b. With the point (-6,1),

1 = (3/2)(-6) + b

1 = (-9) + b

10 = b

So y = (3/2)x + 10

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