Solve (x-3)^2-20=0 for x

x = 3±sqrt(20)

Step-by-step explanation:

(x-3)^2-20=0

Add 20 to each side

(x-3)^2-20+20=0+20

(x-3)^2=20

Take the square root of each side

sqrt((x-3)^2) = ±sqrt(20)

(x-3) = ±sqrt(20)

Add 3 to each side

x-3+3 = 3±sqrt(20)

x = 3±sqrt(20)

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

the first one

step-by-step explanation:

just id the test.