19. The gasoline mileage for two cars can be compared by finding the distance
each car traveled and the amount of gasoline used. The table shows the
distance that car M traveled using x gallons of gasoline. The graph shows the
distance, y, that car P traveled using x gallons of gasoline.
Car M
Car P
Amount of
Gasoline
Distance
(miles)
(gallons)
2
50.4
3
7
5
80.5
181.3
137.5
Distance (miles)
0
1 2 3 4 5
Amount of Gasoline
(gallons)
Based on the information in the table and the graph, compare the
approximate miles per gallon of car M to car P. Show your work or explain
your answer.
Enter your answer and your work or explanation in the space provided.

saving = more money

step-by-step explanation:

if you have 100 bucks, and you want to buy a candy bar, even if you have one at home, if you choose not to buy it, you save.

~courtney

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)