What is the point-slope form of a line that has a slope of –4 and passes through point (–3, 1)?
y minus (negative 3) = negative 4 (x minus 1)
y minus 1 = negative 4 left-bracket x minus (negative 3) right-bracket
Negative 1 minus y 1 = negative 4 (negative 3 minus x 1)
3 minus y 1 = negative 4 (1 minus x 1)

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y - 1 = - 4(x + 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 4 and (a, b) = (- 3, 1), thus

y - 1 = - 4(x - (- 3)), that is

y - 1 = - 4(x + 3)

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step-by-step explanation:

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