What is the domain of the square root function graphed below? On a coordinate plane, a curve open up to the right in quadrant 4. It starts at (0, negative 1) and goes through (1, negative 2) and (4, negative 3).

x ≥ 0

Step-by-step explanation: Domain means the x-value. The graph starts at (0, -1) and then moves right and down. Because the question is asking for the domain, the coordinate you should be looking for is the x coordinate. Find where the x-coordinate begins or ends. It begins at 0 and never goes towards the negative area, however it does go positive for infinite. Lastly, because the line of the graph is a solid hole and not an empty one, 0 is included as an answer. Therefore the domain must be greater or equal to 0.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

2x + 8

step-by-step explanation: