What is the probability of first rolling a 5 and then rolling a 2 on a standard number cube?

1/36

Step-by-step explanation:

There are 6 numbers on a standard cube, 1,2,3,4,5,6

P (5) = 5's / total

        =1/6

P(2) = 2's / total

       = 1/6

Since these are independent events

P(5, then a 2) = P(5) * P(2)

                       = 1/6 * 1/6 = 1/36

Step-by-step explanation:

Step 1:  Find the probability of rolling a 5

Number / Total amount of numbers

Step 2:  Find the probability of rolling a 2

Number / Total amount of numbers

Step 3:  Multiply to get the probability

it has the same slope and a different y-intercept

hope this : )