Suppose an actual census showed that 18.4% of the households in California have incomes in excess of $50,000.
The probability that the sample proportion will be 0.22 or greater for a random sample of 750 households is:

a) 0.0055. b) 0.9945. c) 0.9949. d) 0.0041. e) None

This is a Normal Distribution  problem.

P = 0.184  (18.4% as a decimal)

n = 750

Standard Deviation = Sqrt (P*(1-p) /n) = Sqrt(0.184*0.816/750)  = 0.014149

Normal Distribution  = (0.22-0.184)/0.0141 49 = 0.036/0.0141 = 2.544

2.544 on the Standard Normal Table  = 0.9945

Probability sample is greater: 1 - 0.9945 = 0.0055

Answer is a) 0.0055                

answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.