The distance a car can travel on a certain amount of fuel varies inversely with its speed. If a car traveling 50 mph can travel 300 miles on 10 gallons of fuel, how far could the car travel on 10 gallons of fuel at 60 mph?

2500 miles

Step-by-step explanation:

Since the distance of the car varies inversely with its speed, the distance can be expressed as follows:

   (1)

Where:

d: is the distance

s: is the speed of the car

g: is the gallons of fuel

a: is a constant of proportionality

With the first values, we can find the constant a.

We have:

d = 300 milles

s = 50 mph

g = 10 gallons

Hence, a is:

Now, we can find the distance that the car can travel on 10 gallons of fuel at 60 mph:

Therefore, the car can travel 2500 miles on 10 gallons of fuel at 60 mph.

I hope it helps you!

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.