A bag of gumballs contains 2 pink, 3 orange, 4 blue, 2 red,
and 1 yellow gumballs. Pierre selects two gumballs from the
bag, without replacement. What is the probability that Pierre
selects a yellow and a pink gumball?

Explanation:

1. Sample space

The total number of gums is 2 + 3 + 4 + 2 + 1 = 12.

The number of different outcomes, i.e. the size of the sample space, for the selection of two gumballs from 12 gums is 12 × 11 = 132 different combinations.

2. Number of combinations for the desired outocome.

There are four possible combinations in which one ball is pink and one is yellow:

3. Probability

By definition:

Therefore:

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2