A baseball team has three positions open: first base,
third base, and right field. Six players are trying out
for these positions. In how many different ways can
these positions be filled?

Number of different ways of placing the players are 120

Explanation:

Given:

Three positions in baseball team are there = __  __  __

Number of players trying = 6

Number of ways in which these positions can be filled = ?

6  __  __ in first position, all 6 players have the chances to be positioned

6  5  __ In second position, 5 players have the chances to be positioned

6 5 4 In third position, 4 players have the chances to be positioned.

Therefore, different ways in which the players can be positioned = 6 X 5 X 4

                                                                                                            = 120

-18

step-by-step explanation:

because mean value defines that total sum value over total number of set

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step-by-step explanation: