Give the equation of the circle centered at the origin and passing through the point (0, 10).

Here,

The eqn of circle passing through centre is

x^2+y^2=r^2

Since,it passes through the point(0,10) replace the value of x by 0 and y by 10...

0^2+10^2=r^2

or,100=r^2

therefore,

r=10

The eqn of circle is x^2+y^2=10

HOPE THIS HELPS YOU

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step-by-step explanation:

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh