subject
Mathematics, 06.04.2020 04:52 10040813

3y2+y3βˆ’5)+(4y2βˆ’4y+2y3+8)
(
3
y
2
+
y
3
βˆ’
5
)
+
(
4
y
2
βˆ’
4
y
+
2
y
3
+
8
)

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Answers: 2

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3y2+y3βˆ’5)+(4y2βˆ’4y+2y3+8)
(
3
y
2
+
y
3
βˆ’
5
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