Chords AC and BD intersect at E, with BD = 7 units, DE = 2 units, and AE = 4 units.

What is the length of segment CE?

CE IS 2.5 UNITS

BD=7 units

DE=2 units

AE=4 units

BE=BD-DE=7-2=5 units

By the intersecting chord theorem (when two chords intersect each other inside a circle then the products of their segments are equal )

5/4=x/2

5*2/4=x

10/4=x

2.5=x

CE is 2.5 units

2.5

Step-by-step explanation:

Got it right

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

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