The proportion of brown M&M’s in a milk chocolate packet is approximately 14% (Madison, 2013). Suppose a package of M&M’s typically contains 52 M&M’s. Find the probability that
c.) Six M&M’s are brown. %
d.) Twenty-five M&M’s are brown. %
e.) All of the M&M’s are brown. %
f.) Would it be unusual for a package to have only brown M&M’s? If this were to happen, what would you think is the reason?

Step-by-step explanation:

a)State the random variable.x = number of brown M&Ms in the milk chocolate box.

(b)Argue that this is a binomial analysis.

The binomial analysis includes the following characteristics: 1.Fixed number of measurements.

2. The experiments are autonomous.

3. There are just two results.

4. The expectation of victory will not shift from court to court.

This is a binomial experiment since the number of experiments is set and the measures are independent of each other. In fact, there are only two results – brown M&Ms or not.

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.