Suppose a random variable, x, arises from a binomial experiment. If n = 6, and p = 0.30, find the following probabilities using technology.

a.) P (x=1)

b.) P (x=5)

c.) P (x=3)

d.) P (x=less than equal 3)

e.) P(x=greather than or equal 5)

f.) P(x=less than or equal 4)

Explanation:

Binomial experiments are modeled by the formula:

Where

a.) P (x=1)

b.) P (x=5)

c.) P (x=3)

Using the same formula:

d.) P (x less than or equal to 3)

Also,

You can use either of those approaches. The result is the same.

Using the second one:

e.) P(x greather than or equal to 5)

f.) P(x less than or equal 4)

omg what happend to your question? if you could edit this question i can

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!