Find (f g) (x) for the following f(x) =-12x^3+19x^2 -5 g (x) = 7x^2+15

The answer to your question is (f°g)(x) = -5856x⁶ - 25529x⁴ -52710x² - 36220  

Step-by-step explanation:

Data

f(x) = -12x³ + 19x² - 5

g(x) = 7x² + 15

find (f°g)(x)

Process

1.- Substitute g(x) in all the x of f(x)

    (f°g)(x) = -12(7x² + 15)³ + 19(7x² + 15)² - 5

-Expand

  (f°g)(x) = -12[4913x⁶ + 2205x⁴ + 4725x² + 3375] + 19(49x⁴ + 210x² + 225) - 5

-Simplify

(f°g)(x) = -58956x⁶ - 26460x⁴ - 56700x² - 40500 + 931x⁴ + 3990x² + 4275 -

              5

-Result

(f°g)(x) = -5856x⁶ - 25529x⁴ -52710x²  - 36220  

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the ratio of balloons to tables is 5: 2 and the constant variation is 5.

the equation is y=5x