Nathan invested $3,500 in an account paying an interest rate of 3.5% compounded
quarterly. Assuming no deposits or withdrawals are made, how much money, to the
nearest hundred dollars, would be in the account after 19 years?

\text{Compounded Quarterly:}

Compounded Quarterly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+  

n

r

)  

nt

Compound interest formula

P=3500\hspace{35px}r=0.035\hspace{35px}t=19\hspace{35px}n=4

P=3500r=0.035t=19n=4

Given values

A=3500\left(1+\frac{0.035}{4}\right)^{4(19)}

A=3500(1+  

4

0.035

)  

4(19)

Plug in values

A=3500(1.00875)^{76}

A=3500(1.00875)  

76

Simplify

A=6786.05963486

A=6786.05963486

Use calculator

A\approx 6800

Step-by-step explanation:

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah