On the picture to the right,
AB and AC are segments tangent to circle k(O). OB=3 cm, and OA =6 cm.
Find AB, AC, m∠3, and m∠4.

AB =  5.2

AC =  5.2

m∠3 =  30 degrees

, m∠4 =  30 degrees

Step-by-step explanation:

Triangle ABO and ACO are both 30 60 90 triangles and are equal

Therefore If we have two sides then we can figure out the last side

AB&AC= sqrt27, m<3=30˚, m<4=30˚

Step-by-step explanation:

6^2-3^2= 27, BA & CA= sqrt27

90˚&60˚&30˚ makes a right triangle

angles 3&4 are less than the non-labeled angles, so they have to be 30˚

hi! i think the answer is 1/2 : )

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