Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.
The probability that the sum of the numbers rolled is either even or a multiple of 5 is
The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is

11/18

5/9

Step-by-step explanation:

Make a table showing all the possible sums for two dice:

Of the 36 possible sums, 18 are even, 7 are multiples of 5, and 3 are both even and multiple of 5.  So the probability is:

P(even or multiple of 5) = (18 + 7 − 3) / 36 = 22/36 = 11/18

Of the 36 possible sums, 12 are multiples of 3, 9 are multiples of 4, and 1 is a multiple of both 3 and 4.  So the probability is:

P(multiple of 3 or 4) = (12 + 9 − 1) / 36 = 20/36 = 5/9

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct