A circle with radius 2 units passes through the center A of another circle and intersects it at points B and C. Points A, B, and C divide the circumference of the smaller circle into 3 equal parts. One-tenth of the area of the smaller circle is outside of the bigger circle. What part of the area of the bigger circle is covered by the smaller circle?

did you get the answer yet?

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb