A long jumper leaves the ground at an angle of
22
°

above the horizontal, at a speed of
9

/
m
s

. The height of the jumper can be modeled by
=
h
x
+
−
0.046
x
2
0.362
x

, where
h

is the jumper's height in meters and
x

is the horizontal distance from the point of launch.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

abde or 1,2,4, 5 is the answer

step-by-step explanation:

2x^2+5x+17

your welcome. : )

answer: 10 meter

step-by-step explanation:

need details