Suppose that there are two types of tickets to a show advance and same day. The combined cost of one advance ticket and one same-day ticket is $70.For one performance 35 Advance tickets and 25 same day tickets were sold the total amount paid for the ticket was 2150 what was the price of each kind of ticket

Step-by-step explanation:

There are two types of tickets to a show, advance and same day tickets.

Let the advance ticket be represented as x and same day ticket as y.

The combined cost of one advance ticket and one same-day ticket is $70.

x + y =  70   (1)

For one performance 35 Advance tickets and 25 same day tickets were sold the total amount paid for the ticket was 2150

35 x + 25 y = 2150  ... (2)

multiply eq (1) by 25, we get

25 x + 25 y  = 1750  ... (3)

subtract eq (3) from (2), we get

10 x = 400,

x = 40, substitute in eq (1)

40 + y = 70

y = 30

The cost of an advance ticket = $40

The cost of an same day ticket = $30

11

step-by-step explanation:

32.50-7.50=25

225/25=11

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!