Simplify without the absolute value |x+3| ; if x>2

if

Step-by-step explanation:

Recall some following basic ideas about absolute value:

or I guess

or just but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at alone for a second.

* if is positive or zero.

When is positive or zero? [greater than or equal to 0]

Subtract 3 on both sides

* if is negative or zero.

When is negative or zero? [less or equal to 0]

Subtract 3 on both sides

So looking at the bullet points (the *), fits into the first inequality.

Therefore, .

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.