The difference between two positive rational numbers is 2/9 . The numerator of the first number is 4 times larger than the numerator of the second, and its denominator is 3 times larger. Find the largest of these rational numbers?

Let the 2nd fraction be a/b then according to question,

1st fraction is 4a/3b

Now,

4a/3b-a/b=2/9

(4a-3a)/3b=2/9

a/3b=2/9

compairing corresponding elements of fraction,

a=2

And,

3b=9

b=3

the first one

step-by-step explanation:

just id the test.